Question

if sin thita = 12/13 and lies in the second quadrant , find the value of sec+tan.​

Answer 1

Answer:

-5

Step-by-step explanation:

As we know, in second quadrant, sin x and cosec x are positive and all other ratios are negative. On using the formulas, cos x = √(1 - sin2 x) = – √(1 - (12/13)2) = – √(1 - (144/169)) = – √(169 - 144)/169 = -√(25/169) = – 5/13 As we know, tan x = sin x/cos x sec x = 1/cos x Then, tan x = (12/13)/(-5/13) = -12/5 sec x = 1/(-5/13) = -13/5 sec x + tan x = -13/5 + (-12/5) = (-13 - 12)/5 = -25/5 = -5 Thus, sec x + tan x = -5

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