Math, asked by ektanikam7, 3 months ago

If sin thita= 3/5 find cos thita ?​

Answers

Answered by jamshishams36
0

Answer:

Hypotenuse =5

Opposite =3

Adjacent =4

Cos thita=4/5

Step-by-step explanation:

Hope it help you

Answered by sshubhangi272
1

Step-by-step explanation:

ΔABC be a right angled at B

Let ∠ACB=θ

Given that, sin θ = 3/5

AB/AC = 3/5

Let AB = 3x

then AC = 5x

In right angled ΔABC,

By Pythagoras theorem,

We get

(5x)

2

=(3x)

2

+BC

2

BC

2

=(5x)

2

−(3x)

2

BC

2

=(2x)

2

BC=4x

(i) cos θ = Base/ Hypotenuse

= BC / AC

= 4x /5x

= 4/5

(ii) tan θ = perpendicular/Base

= AB/BC

= 3x/4x

=3/4

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