Question

If sin thita=3/5 then find the value of sin^2thita-cos^2 thita?​

Answer 1

Answer:

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Step-by-step explanation:

sinФ = 3/5

Also, cos²Ф = 1 - sin²Ф

sin²Ф - cos²Ф = 2sin²Ф - 1

                       = 2 * 9/25 - 1

                       = 18/25 - 25/25

                       = -7/25

Answer 2

$\sin(theta) = \frac{perpendicular}{hypotensue}$

Let the each side of the triangle be X

so,the perpendicular side to theta is 3x

and hypotensue is 5x

hypontensue^2 = base^2 + perpendicular^2

=>Base = √hypo^2-perpn.^2

=>Base = √ 5x^2-3x^2

=> Base = 4x

cos theta = base//hypotensue

=>cos theta = 4x/5x = 4/5

sin^2 theta - cos^2 theta

=>( sin theta + cos theta )( sin theta - cos theta)

=> (3/5+4/5)(3/5-4/5)

=>7/5 X -1/5

=>-7/25

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