Question

if sin thita = 3/5 then the value of 1-cos2thita is​

Answer 1

Answer:

Step-by-step explanation:

sin tita =3÷5. then (1-cos^2tita)=? NOW (1-COS^2tita)=sin^2. then sin^2tita=(3÷5)^2. = 9÷25

Answer 2

Step-by-step explanation:

given,

$\sin( \alpha ) = \frac{3}{5}$

=>

$\cos( \alpha ) = \sqrt{1 - { \sin {}^{2} ( \alpha ) } }$

cosa = √ 25-9/25 = 4/5

we know,

$\cos(2 \alpha ) = \cos {}^{2} \alpha - \sin {}^{2} \alpha$

=> cos 2a = 16/25 - 9/25 = 7/25

thus,

1 - cos2a = 1 - 7/25 = 18/25