Question

If sin thita =40 /41 . find cos thita and tan thita​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

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Cos (thita)= 9/41

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Tan (thita)= 40/9

Step-by-step explanation:

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$\sin( \alpha ) = \frac{40}{41} = \frac{perpendicular}{hypotenuse} \\ \\ perpendicular \: = 40 \: \: and \: hypotenuse = 41 \\ \\ now \: by \: pythagoras \: theorem \\ \\ {(h)}^{2} = {(b)}^{2} + {(p)}^{2} \\ \\ {(41)}^{2} = {(b)}^{2} + {(40)}^{2} \\ \\ 1681 = {(b)}^{2} + 1600 \\ \\ 1681 - 1600 = {(b)}^{2} \\ \\ 81 = {(b)}^{2} \\ \\ now \: taking \: square \: root \: on \: both \: sides \\ \\ \sqrt{81} = \sqrt{ {(b)}^{2} } \\ \\ b(base) = 9 \\ \\ now \: \cos( \alpha ) = \frac{base}{hypotenuse} = \frac{9}{41} \\ \\ \tan( \alpha ) = \frac{perpendicuar}{base} = \frac{40}{9} \\ \\ this \: is \: ur \: required \: answer \: :):):):):)$