if sin thita,cos thita are roots of the equation ax2 +bx+c=0
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sin∅ , cos∅ are the roots of ax² + bx + c = 0
sum of roots = sin∅+cos∅ = -b/a
sin∅ + cos∅ = -b/a -----(1)
product of roots =sin∅.cos∅ = c/a ----(2)
From eqn (1)
take square both sides
sin²∅ + cos²∅ +2sin∅.cos∅ = b²/a²
1 + 2(c )/a = b²/a²
a² + 2ac = b²
sum of roots = sin∅+cos∅ = -b/a
sin∅ + cos∅ = -b/a -----(1)
product of roots =sin∅.cos∅ = c/a ----(2)
From eqn (1)
take square both sides
sin²∅ + cos²∅ +2sin∅.cos∅ = b²/a²
1 + 2(c )/a = b²/a²
a² + 2ac = b²
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