Question

if sin thita = root 5 upon 2 root 3 and tan thita = root 5 upon 7, then what is the value of cos thita ?​

Answer 1

tanA=sinA/cosA

=(√5/2√3)/cosA

cosA= (√5/2√3)/tanA.

(√5/2√3)/(√5/7).

(7√5)/(2√3×√5).=7/2√3