Question

if sin thita =underroot 3/2,find cosecthita +cot thita
only 3 is in root 2 is not​

Answer 1

$\Huge{\underline{\underline{\mathfrak{Answer \colon}}}}$

To Prove

cosec∅ + cot∅ = 3√2

Given that

$\sf{sin \theta = \frac{ \sqrt{3}}{2} }$

Thus,

$\sf{sin \theta \: = sin60} \\ \\ \huge{\rightarrow \: \sf{ \theta \: = 60}}$

Now,

$\sf{cosec60 \: + \: cot60 } \\ \\ = \frac{2}{ \sqrt{3} } + \frac{1}{ \sqrt{3} } \\ \\ = \frac{3}{ \sqrt{3} } \\ \\ = \underline{\boxed{ \sqrt{3} }}$

Thus,the value of cosec60 + cot60 is √3