Question

if Sin tita=1/3 then tan tita=?​

Answer 1

Answer:

$1 \div 2 \sqrt{2}$

Explanation:

$pyothogores \:t \: heorem \\ \: = x {}^{2} = 3 {}^{2} - 1 {}^{2} \\ = x {}^{2} = 9 - 1 \\ x {}^{2} = 8 \\ x = 2 \sqrt{2} .$

tan teta = 1/2 root2