if sin tita=12/13 then find the cost of cos tita and tan tita
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cos Ѳ = 5/13
tan Ѳ = 12/5
Step-by-step explanation:
sinѲ = 12/ 13
Since, sinѲ = perpendicular/hypotenuse
Let perpendicular be 12x and hypotenuse be 13x
According to Pythagoras Theorem:
(hypotenuse)² = (perpendicular)² + (base)²
=> (13x)² = (12x)² + (base)²
=> 169x² = 144x² + (base)²
=> 169x² - 144x² = (base)²
=> 25x² = (base)²
=> base = √25x²
=> base = 5x
Therefore,
cosѲ = base/hypotenuse = 5x/13x = 5/13
tanѲ = perpendicular/base = 12x/5x = 12/5
Hope it helps you......✔✔✔
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