Question

If sin tita =21/29 then the value of sec tita +tan tita,if tita lies between 0 and pi/2

Answer 1

sin tita=21/29

therefore cos tita =(1-sin^2 tita)^1/2

cos tita=(1-(21/29)^2)^1/2

cos tita =[(841-441)/841]^1/2

cos tita=20/29

therfore sec qetha= cos tita^-1

therfore sec tita=29/20

tan tita=sin tita/cos tita=21/20

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