Question

if sin tita =4/5.what is the valu of cot^2 tita

Answer 1

Let ABC be a right angled triangle at B.

=) sin thita at C = AB/AC

=) 4/5 = AB/AC

Hence base (BC) ^2 = 5^2 - 4^2

=) BC ^2 = 25-16=9

=) BC = 3.

Since cot thita = b/p

= BC/AB = 3/4

Hence cot ^2 thita = (3/4)^2

= 9/16.

Hope it's helpful to u.

Answer 2

if the value of sin thetha = 4/5
as we know that sin thetha = prependicular / hypotenous
so, prependicular=4 & hypotenous =5
base = (h)^2-(p)^2 = 3
now, we know that cot thetha = base /prependicular
cot^2 thetha = (3)^2/(4)^2 =9/16