Question

if sin (tuta) = 11 / 61 then find cos (tita)​

Answer 1

Answer:

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Answer 2

Answer:

cos(theeta) = 60/61

Step-by-step explanation:

Acc to definition,

sin(theeta) = P/H and cos(theeta) = B/H

so here

sin(theeta) = P/H = 11 / 61

cos(theeta) = B/H =?

On applying Pythagoras theorem

H^2 = P^2 + B^2

61^2 = 11^2 + B^2

3721 = 121 + B^2

3721-121 = B^2

B^2 = 3600

B = √3600

B = 60

Therefore

cos(theeta) = B/H = 60/61