Question

*If sin x = 0 , then x is equal to:*

1️⃣ nπ, where n ∈ Z
2️⃣ 2nπ + x, where n ∈ Z
3️⃣ nπ + x, where n ∈ Z
4️⃣ None of these​

Answer 1

Answer:

whenever sinx=0 , we have that: x=π±kπ for all k in the set of integers. That is, if k=0,1,2,...,N , where N is some arbitrarily large integer, then sinx=0 for x=0,±π,±2π,...,±2Nπ .

Step-by-step explanation:

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Answer 2

Answer:

1

Step-by-step explanation:

because at all integer multiple of π sin x is 0