If Sin x = 1/√2, then value of Cos x will be
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Procedure:
we know that
sin^2(x) + cos^2(x)=1
now
(sin x - cos x)^2 = sin^2 (x) - 2 sin(x)*cos(x) + cos^2(x)
(sin x - cos x)^2 = sin^2(x) + cos^2 - 2 sin(x) * cos (x)
(sin x - cos x)^2 = 1 - 2* 1/2
put the value from given information in the question and sin^2(x) + cos^2(x)=1
(sin x - cos x)^2 = 0
sin x -cos x = 0
if any doubt comment below
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Answer: 1/√2
Step-by-step explanation:
Sinx=1/√2
The value of sinx is 1 /√2 when the angle x is 45°
x=45°
Cosx = cos45° = 1/√2
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