Question

if sin(x-20)°=cos(3x-1)° then find the value of x​

Answer 1

Bro here is your ans

Hope it is correct

Answer 2

Answer:

sin(x - 20) = cos(3x -1)

= > cos [90-(x - 20)] = cos(3x-1)

= > 90 -(x - 20) = 3x -1

= > 90 - x + 20 = 3x - 1

= > 110 + 1 = 3x +x = 4x

=> x = 111/4

= 27.75°