If sin(x-20) ° =cos(3x-10) ° , then x is :
(A) 60 (B) 30 (C) 45 (D) 35.5
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sin(x-20)=cos(3x-10)
➡sin(x-20)=sin[90-(3x-10)]-----[sin(90-theta)=cos theta]
➡sin(x-20)=sin(90-3x+10)
➡sin(x-30)=sin(100-3x)
Cancelling sin from both the sides,
➡x-30=100-3x
➡x+3x=100+30
➡4x=130
➡x=32.5
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