Question

If sin (x-20)° = cos (3x - 10)', then 'x'
is
​

Answer 1

Question:-

• Find the value of x.

Solution:-

Given,

$\sf \sin(x - 20 \degree) = \cos(3x - 10 \degree)$

$\sf \implies \cos(90 \degree - (x -20 \degree) ) = \cos(3x - 10 \degree)$

$\sf \implies \cos(110 \degree - x) = \cos(3x - 10 \degree)$

$\sf \implies 110 - x = 3x - 10$

$\sf \implies 4x = 120 \degree$

$\sf \implies x = 30\degree$

Hence, the value of x is 30°.