If sin(x - 2y) = cos (4y - x)
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Answered by
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Heya ❗
here's Ur answer ❗
= sin ⊘ = cos (90 - ⊘)
= cos { 90 - (x - 2y)] = cos (4y - x)
= 90 - (x - 2y) = 4y - x
= 90 - x + 2y = 4y - x
glad help you
it helps you
thanks
here's Ur answer ❗
= sin ⊘ = cos (90 - ⊘)
= cos { 90 - (x - 2y)] = cos (4y - x)
= 90 - (x - 2y) = 4y - x
= 90 - x + 2y = 4y - x
glad help you
it helps you
thanks
arihantjain7800:
thanks
Answered by
1
Hello Friend..❤️❤️
The answer of u r question is..✌️✌️
If sin(x+2y)=cos (4y-x)
Ans:✍️✍️✍️✍️✍️✍️✍️✍️✍️✍️
Sin tita = cos(90-tita)
cos[90-(x-2y)]=cos4y-x
=90-(x-2y)=4y-x
=90-x+2y=4y-x
Hence proved.
Thank you..⭐️⭐️⭐️
The answer of u r question is..✌️✌️
If sin(x+2y)=cos (4y-x)
Ans:✍️✍️✍️✍️✍️✍️✍️✍️✍️✍️
Sin tita = cos(90-tita)
cos[90-(x-2y)]=cos4y-x
=90-(x-2y)=4y-x
=90-x+2y=4y-x
Hence proved.
Thank you..⭐️⭐️⭐️
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