Question

If sin (x – 2y) = cos (4y - x), then the value of cot 2y is:
(a) o
(b) 1
(c) 1/root 3
(d) undefined​

Answer 1

Answer:

cot 90° = 0

Step-by-step explanation:

sin β = cos(90 - β)

~~~~~~~~

sin(x - 2y) = cos(4y - x)  

sin(x - 2y) = cos[90 - (x - 2y)]

cos[90° - (x - 2y)] = cos(4y - x)

90 - x + 2y = 4y - x

2y = 90°

cot 90° = 0