Question

If sin x = 4/5 , how do you find cos x?

Answer 1

$sinx = \frac{4}{5} = \frac{perpendicular}{hypotenuse} \\ cos = \frac{base}{hypotenuse} \\ \\ by \: pythagaos \:theorm \\ {h}^{2} = {b}^{2} + {p}^{2} \\ {5}^{2} = {b}^{2} + {4}^{2} \\ 25 = {b}^{2} + 16 \\ {b}^{2} = 9 \\ b = \sqrt{9 } \\ b = 3 \\ cos = \frac{base}{hypotenuse} = \frac{3}{5}$
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