if sin x = √5/3 and 0<x<π/2, find the value of sin 2x
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Sin2x=2sinx*cosx
=2*root5/3*whole root1-5/9
=2root5/3*2/3
=4root5/9
=2*root5/3*whole root1-5/9
=2root5/3*2/3
=4root5/9
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