Math, asked by sumanhalder3390, 7 months ago

If sin x + cos x = √2 sin (90-x), then value of cot x is equal to-

Answers

Answered by STarAK

1

Answer:

given,sin x + cos x = √2sin (90-x)

Step-by-step explanation:

sinθ+cosθ=√2cos(90- θ)

= sinθ + cosθ = √2sinθ

= (sinθ + cosθ)/sinθ = √2sinθ/sinθ [dividing both sides by sinθ ]

= 1 + cotθ = √2

= cotθ = √2-1

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