If sin x + cos x = a and sec x + cosec x= b then b (a² − 1) =
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Step-by-step explanation:
sinx+cosx=a
(sinx+cosx)²=a²
sin²x+cos²x+2sinxcosx=a²
1+2sinxcosx=a²
2sinxcosx=a²-1
sinxcosx=(a²-1)/2
secx+cscx=b
1/cosx+1/sinx=b
(sinx+cosx)/sinxcosx=b
a/(a²-1)/2=b
2a/(a²-1)=b
2a=b(a²-1)
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Answer:
The answer is..
I think-
2(sinx+cosx)
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