if sin x degree =0.67 find the value of—(i) cos x degree +tan x degree
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sinx = 0.67 = 2/3
Hypotenuse is 3 , One side is 2 .
Another side = √3²-2² = √5 .
Now cosx + tanx
= √5 / 3 + 2/√5
= 5+6/3√5
= 11/3√5
= 11/3√5 * √5/√5
= 11√5 / 15
= 1.63
{ or }
sinx = 0.67
sin²x+cos²x = 1
cos²x = 1 - (0.67)²= 1- 0.36 = 0.64
cosx = ±0.64 .
tanx = 0.67/0.64 = 1.04
Now cosx + tanx = 0.64 + 1.04 = 1.68
(or) 1.04 - 0.64 = 0.38
Hypotenuse is 3 , One side is 2 .
Another side = √3²-2² = √5 .
Now cosx + tanx
= √5 / 3 + 2/√5
= 5+6/3√5
= 11/3√5
= 11/3√5 * √5/√5
= 11√5 / 15
= 1.63
{ or }
sinx = 0.67
sin²x+cos²x = 1
cos²x = 1 - (0.67)²= 1- 0.36 = 0.64
cosx = ±0.64 .
tanx = 0.67/0.64 = 1.04
Now cosx + tanx = 0.64 + 1.04 = 1.68
(or) 1.04 - 0.64 = 0.38
SERPENTINE:
the answer is incorrect but thanks for trying
what's the actual answer?
1.6448 is the real answer
you may take it as approximation dude
it's alright thanks a lot
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0
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I have provided answer in this image plz check it out.... Hope it helps you i have also checked the answer in my book its correct
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