if sin x =k sin (x +y) show that tan(x+y)=sin y/cos y-k
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Answer:
sin(x-y)=sin(x)cos(y)- cos(x)sin(y)
And
sin(x+y)=sin(x)cos(y)+cos(x)sin(y)
Thus,
sin(x)cos(y)- cos(x)sin(y)=k[sin(x)cos(y)+cos(x)sin(y)]
Divide both LHS and RHS by cos(x)cos(y) and you get:
[sin(x)cos(y)- cos(x)sin(y)]/cos(x)cos(y)=k[sin(x)cos(y)+cos(x)sin(y)]/cos(x)cos(y)
tan(x)-tan(y)=k[tan(x)+tan(y)]
(1-k)tan(x)=(1+k)tan(y)
tan(x)=[(1+k)/(1-k)]tan(y)
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