Question

if sin x = root3/2 then find the value of ( cosec x + cot x)

Answer 1

Answer:sin x=√3/2

sin x=sin 60°. Sin x=√3/2

x=60°

cosec x+ cot x

=1/sin x + sin x/cos x

=cos x + sin^2 x/sinxcosx

=cos 60+sin^2 60/sin 60cos 60

=(1/2+3/2)/(√3/2)(1/2)

=2/√3/2√2

=4√2/√3

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Answer 2

Answer:5√3/3

Step-by-step explanation:

Sinx=√3/2

x=60°

So,

Cosecx+cotx=cosec60°+cot60°

2√3/3 +√3

=5√3/3