if sin x/sin y=3 and cos x/cos y=1/2 then find the value of 116[sin2x/sin2y÷cos2x/cos2y]
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Answered by
1
Step-by-step explanation:
sin2x=2sinxcosx
cos2x=1-2sin^2x
sin2y=2sinycosy
cos2y=1-2sin^y
116{(2sinxcosx/2sinycosy)/(1-2sin^2x/1-2sin^2y)}
now simply this you will get your ans
Answered by
0
Answer:
aNS 24
Step-by-step explanation:
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