if (sin x + sin y )= "a" and (cos x + cos y )= "b" than prove , cos (1/2) (x-y)= +_ (1/2 )√(a^ 2 +b^ 2)
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Answer:
Step-by-step explanation:
(cosx+cosy)
2
+(sinx−siny)
2
=(cos
2
x+cos
2
y+2cosxcosy)+(sin
2
x+sin
2
y−2sinxsiny)
=(cos
2
x+sin
2
y)+(cos
2
x+sin
2
y)+2(cosxcosy−sinxsiny)
=1+1+2cos(x+y)
=2+2cos(x+y)
=2[1+cos(x+y)]
=4 cos
2
(
2
x+y
) = RHS
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