Question

if sin x +sin y=root3 (cosy-cosx) then sin3x/sin 3y

Answer 1

solution of your question given below:

sinx+siny = root3 ( cosx-cosy)

2sin(x+y/2)cos(x-y/2) = root3 {2sin(x+y/2)sin(y-x/2)}

sin(x+y/2)[cos(x-y/2)-root3. sin(y-x/2)]=0

sin(x+y/2)= 0

x= -y.1

or cos(x-y/2)=root3. sin(y-x/2)

tan(x-y/2)=- 1/root3

then x-y/2 = - pie/6

x = - pie/3 +y.2

putting the value of x from 1 & 2 in sin3x+sin3y we get the required answer

Answer 2

Answer:

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