if sin^x (x-y)/X+y=a Shaw that du/dx=y/x
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Answer:Let us find
d
2
y
d
x
2
for
x
3
+
y
3
=
1
.
First, let us find
d
y
d
x
.
x
3
+
y
3
=
1
by differentiating with respect to
x
,
⇒
3
x
2
+
3
y
2
d
y
d
x
=
0
by subtracting
3
x
2
,
⇒
3
y
2
d
y
d
x
=
−
3
x
2
by dividing by
3
y
2
,
⇒
d
y
d
x
=
−
x
2
y
2
Now, let us find
d
2
y
d
x
2
.
by differentiating with respect to
x
,
⇒
d
2
y
d
x
2
=
−
2
x
⋅
y
2
−
x
2
⋅
2
y
d
y
d
x
(
y
2
)
2
=
−
2
x
(
y
2
−
x
y
d
y
d
x
)
y
4
Step-by-step explanation:
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