Question

if sin0=12/13 find the values of cos0 and tan0​

Answer 1

Answer:

$sin \alpha = \frac{12}{13} = \frac{p}{h} \\ so \: p = 12 \: and \: h = 13 \\ by \: pythagoras \: theorem \\ {h}^{2} = {b}^{2} + {p}^{2} \\ {b}^{2} = 169 - 144 \\ {b}^{2} = 25 \\ \bold{b = 5} \\ cos \alpha = \frac{b}{h} = \frac{5}{13} \: \: \: and \: \\ tan \alpha = \frac{p}{b} = \frac{13}{5} \\ hope \: it \: helps \: u....$

Answer 2

Answer:

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