Question

if Sin0 = 3/4
then find the value of Sec0 and tan0

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Answer 1

Answer:

kindly see the answer below....

Step-by-step explanation:

Here, given that,

$\sin(x) = \frac{3}{4}$

then, we have to find out the value of

$\sec(x) \: \: and \: \: \tan(x)$

therefore, according to the triangle rule,

perpendicular =3

base=√7

and, hypotenuse = 4

so,

$\sec(x) = \frac{hypotenuse}{base}$

$or \: \: \sec(x) = \frac{4}{ \sqrt{7} }$

and,

$\tan(x) = \frac{perpendicular}{base}$

$or \: \: \tan(x) = \frac{3}{ \sqrt{7} }$

thanks a lot....