Question

if sin0=4/5, what is the value of cot²0 ​

Answer 1

Answer:

=9/16

Step-by-step explanation:

sin0= 4/5

sin=p/h=4/5

let b= 3k,h=5k

base= √5^2-4^2

= 3k

cot^2 =(b/p)^2

3k/4k

=(3/4)^2

=9/16

Answer 2

Given :-

SinØ = 4/5

To find :-

Cot²Ø

As we know that,

SinØ = P/H

P/H = 4k/5k

By Pythagoras Theorem,

B² = H² - P²

B² = (5k)² - (4k)²

B = √25k² - 16k²

B = 3k

Now,

CotØ = B/P

CotØ = 3k/4k

CotØ = 3/4

Squaring both the sides.

Cot²Ø = 9/16