Question

if sin0 =a/b then cos0 is?​

Answer 1

Step-by-step explanation:

Sinθ=a/b

∴, cosθ=√(1-sin²θ) [∵, sin²θ+cos²θ=1]

or, cosθ=√(1-a²/b²)

or, cosθ=√{(b²-a²)/b²}

or, cosθ=√(b²-a²

Answer 2

Step-by-step explanation:

if sin0 then the value of a=0

then the value of cos0 is x/b where x =base of the triangle