Math, asked by sheefachennai, 6 months ago

if sin0 and cos0 are the roots of the equation ax^2+bx+c=0 prove that a^2-b^2+2ac=0

Answers

Answered by akshansh27
0

If sinθ and cosθ are the roots of the equation ax2−bx+c=0, then which one of the following is correct?

A

a2+b2+2ac=0

B

a2−b2+2ac=0

C

a2+c2+2ab=0

D

a2−b2−2ac=0

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ANSWER

ax2−bx+c=0

sinθ and cosθ are roots.

∴sinθ+cosθ=ab;sinθ cosθ=ac

Then (sinθ+cosθ)=a2b2

or sin2θ+cos2θ

Answered by sanjanakumari54
2

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