if sin0 and cos0 are the roots of the equation ax^2+bx+c=0 prove that a^2-b^2+2ac=0
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If sinθ and cosθ are the roots of the equation ax2−bx+c=0, then which one of the following is correct?
A
a2+b2+2ac=0
B
a2−b2+2ac=0
C
a2+c2+2ab=0
D
a2−b2−2ac=0
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ANSWER
ax2−bx+c=0
sinθ and cosθ are roots.
∴sinθ+cosθ=ab;sinθ cosθ=ac
Then (sinθ+cosθ)=a2b2
or sin2θ+cos2θ
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