Question

if sin0= cosec0 and 0‹0‹π,then the value of 0 is

(a) π
(b) π/2
(c)π/4
(d) 0°​

Answer 1

Answer:

$\huge{\boxed{\underline{\underline{\tt{Solution}}}}}$

Given,

sin θ + cos θ = 0

sin θ = -cos θ

(sin θ)/ cos θ = -1

tan θ = -1

Since 0 < θ < π

Therefore, tan θ = tan 3π/4

θ = 3π/4

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Answer 2

(d) 0°

sin θ + cos θ = 0

sin θ = -cos θ

(sin θ)/ cos θ = -1

tan θ = -1

Since 0 < θ < π

Therefore, tan θ = tan 3π/4

θ = 3π/4

I hope it is helpful for you