if sin0+sin^20=1 find cos^20+cos^40
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Question :
If sin@ + (sin@)^2 = 1 ,then find the value of : (cos@)^2 + (cos@)^4.
Note:
(sin@)^2 + (cos@)^2 = 1
Or
(sin@)^2 = 1 - (cos@)^2
Solution:
Give:
sin@ + (sin@)^2 = 1 -------(1)
To find:
(cos@)^2 + (cos@)^4 = ?
We have;
=> sin@ + (sin@)^2 = 1
=> sin@ = 1 - (sin@)^2
=> sin@ = (cos@)^2 --------(2)
{ (sin@)^2 = 1 - (cos@)^2 }
Now,
Squaring both sides in eq-(1)
We get;
=> (sin@)^2 = {(cos@)^2}^2
=> (sin@)^2 = (cos@)^4 ----------(3)
Thus;
(cos@)^2 + (cos@)^4
= (sin@) + (sin@)^2 {using eq-(2),(3)}
= 1 {using eq-(1)}
Hence,
The required value of the
(cos@)^2 + (cos@)^4 is 1.
Anonymous:
Good work keep going :)
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