if sin135-cos240/sin135+xos240=a+rootb then b=
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sin(90+45)-cos(180+60)/sin(90+45)+cos(180+60)
=cos45-[-cos60]/cos45+(-cos60)
=(1/√2)-(-1/2)/(1/√2)+(-1/2)
=(1/√2)+(1/2)/(1/√2)-(1/2)
=1/√2+1/√2-1/2
=-1/2+√2
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