If sin17degree = x/y then proved that , sec17degree - sin73degree = x^2 / y√(y^2 - x^2)
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Answer:
X2/y√y2-x2
Step-by-step explanation:
sin 17=x/y
cos 17=√y2-x2/y
sec 17=y/√y2-x2..............(1)
sin 73=√y2-x2/y...............(2)
sec 17- sin 73
=y/√y2-x2-√y2-x2/y
y2-(y2-x2)/y√y2-x2
X2/y√y2-x2
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