If sin²θ cos²θ θ (1 + tan²θ ) (1 + cot² θ) = λ, then find the value of λ.
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Answer:
The value of λ is 1 .
Step-by-step explanation:
Given : sin²θ cos²θ θ (1 + tan²θ ) (1 + cot² θ) = λ
sin²θ cos²θ (sec²θ ) (cosec² θ) = λ
[By using an identity,1 + tan² θ = sec² θ ,cot² θ + 1 = cosec² θ]
(sin²θ × cosec² θ) × (cos²θ × sec²θ ) = λ
(sin²θ × 1/sin² θ) × (cos²θ × 1/cos²θ ) = λ
[cosecθ = 1/ sinθ, secθ = 1/cosθ]
1 × 1 = λ
λ = 1
Hence, the value of λ is 1 .
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The above attachment contains step-by-step-explanation with answer.
➟ λ = 1
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