Question

if sin2A=2sinA A=0° 3tanQ=5

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Answer 1

Step-by-step explanation:

sin2A=2sinA

⇒2sinAcosA=2sinA

⇒2sinA(cosA−1)=0

⇒sinA=0,cosA−1=0

⇒sinA=0,cosA=1

sinA=0⇒A=0,π,2π

cosA=1⇒A=0,2π

∴A={0,π,2π}∩{0,2π}

={0,2π}

Hence A=0

thank you

may be my answer is right