Question

If sin2A =9cos(A-18) then find the value of A

Answer 1

HERE IA YOUR ANSWER MATE

$question$

sin2A=9cos(A-18)

$answer$

Convert sin2A=Cos(90-2A),we have

Cos(90-2A)=Cos (A-18)

Cutting cos on both side,we have

90-2A=A-18

90+18=A+2A

3A=108

A=108÷3

A=36

PLZZZ MARK BRAINLIEST