Question

If sin2A= cos (A-18°), then find the value of A.

Answer 1

Answer:

Hello Brother.....

Step-by-step explanation:

$we \: know \: that \: \sin(90 - a ) = cosa$

So by writing

Sin2A = cos(90°-2A)

cos(90°-2A) = cos(A-18°)

dividing cos by cos we get...

90°-2A = A-18

Now by solving....

we get

A = 36°

Hope this may help you

Otherwise report it......