if sin²a=cos²a then find cot⁶a-cot²a
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cot^6 a - cot^2 a
(cot^2)^3 - cot ^2 a
{(cos^2 a /sin^2 a) ^3}. - cos^2 a / sin^2 a
it is given that sin^2 a = cos^2 a
so (cos^2 a / cos^2 a) ^3 - cos^2 a / cos^2 a
1^3 - 1
1 - 1. = 0
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