If sin2A+sinA=1
Prove cos2A+cos4A=1
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Answered by
5
We have,
sinA + sin²A = 1 ...(1)
⇒ sinA = 1 – sin²A ...(2)
Now
cos²A +
= (1 – sin²A) + {(1 – sin²A)}²
= sinA + sin²A [from (2)]
= 1 [from (1)]
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Answered by
2
sin^2A + sin A = 1 -------(2)
we know that,
sin^2 A + cos^2 A = 1 -------(1)
By comparing equation (1) & (2) we get to know ;
sinA = cos^2 A ---------(3)
squaring both sides ;
sin^2 A = cos^4 A ------(4)
==========================
Now ,
L.H.S
= cos^2 A + cos^4 A
Put the values from equation (3) & (4)
= sin A + sin^2 A
= equation (1)
= 1
= R.H.S
---------------- Hence Proved
-------------------------------
we know that,
sin^2 A + cos^2 A = 1 -------(1)
By comparing equation (1) & (2) we get to know ;
sinA = cos^2 A ---------(3)
squaring both sides ;
sin^2 A = cos^4 A ------(4)
==========================
Now ,
L.H.S
= cos^2 A + cos^4 A
Put the values from equation (3) & (4)
= sin A + sin^2 A
= equation (1)
= 1
= R.H.S
---------------- Hence Proved
-------------------------------
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