Question

If sin²theta + 3cos2theta = 4 show that tan theta = 1√3​

Answer 1

$\huge{\mathcal{\underline{\green{SOLUTION}}}}$

let theta be A

7sin²A+3cos²A=4

4sin²A+3(sin²A+cos²A)=4

4sin²A+3=4

Sin²A=1/4

SinA=1/2

Sin30=1/2

A=30

tan30=1/√3

Hence, tanA=1/√3

Answer 2

Step-by-step explanation:

let theta be A

7sin²A+3cos²A=4

4sin²A+3(sin²A+cos²A)=4

4sin²A+3=4

Sin²A=1/4

SinA=1/2

Sin30=1/2

A=30

tan30=1/√3

Hence, tanA=1/√3