If sin2X=3/4,then sin^3X+cos^3X=
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Step-by-step explanation:
So I got the following equation:
sin3x∗cos3x=sin2x
so I used the formula
sina∗cosb=1/2(sin(a+b)+sin(a−b))
but don't know how to continue. Here is my solution so far:
sin3x∗cos3x=sin2x
1/2(sin(3x+3x)+sin(3x−3x))=sin2x
1/2(sin(6x)+sin(0))=sin2x
1/2sin6x=sin2x
What is my next step to continue? Thanks.
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