Math, asked by saquibimranshah, 9 months ago

If sin2X=3/4,then sin^3X+cos^3X=​

Answers

Answered by AvinashJaybhaye
4

Step-by-step explanation:

So I got the following equation:

sin3x∗cos3x=sin2x

so I used the formula

sina∗cosb=1/2(sin(a+b)+sin(a−b))

but don't know how to continue. Here is my solution so far:

sin3x∗cos3x=sin2x

1/2(sin(3x+3x)+sin(3x−3x))=sin2x

1/2(sin(6x)+sin(0))=sin2x

1/2sin6x=sin2x

What is my next step to continue? Thanks.

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