Question

If sin2x cos y=(a^(2)-1)^(2)+1 and cos2x sin y =a+1 where x y in 0 pi and a in R then number of ordered pairs (x y) is​

Answer 1

Answer:

sinx.cosy=1

⇒sinx=1,cosy=1 or sinx=−1,cosy=−1

Hence, the ordered pairs of (x,y) are

(x,0), (x, 2x) (3x,X) ans..

2 2 2