Question

If sin2x=$\frac{2tan30°}{1+tan^{2} 30°}$, then find the value of $\frac{1-cot^2 x}{1+cot^2 x}$, where 0°

Answer 1

Step-by-step explanation:

this is the answer of question

Answer 2

Answer:

The value of

\frac{2tan30}{1-tan^{2}30} = $\sqrt{3}$

Step-by-step explanation:

______________________

we know that,

\boxed {\frac{2tanA}{1-tan^{2}A}=tan2A}

______________________

Here ,

A = 30°

\frac{2tan30}{1-tan^{2}30}

= tan(2\times 30)

= tan60°

= \sqrt{3}

Therefore,

The value of

\frac{2tan30}{1-tan^{2}30} = $\sqrt{3}$